Below is a simplified force diagram representing two Sumo wrestlers attempting to push eachother out of the ring. Note that the box in the middle is there to help you visualize.

To solve this problem, we need to analyze the forces acting on the two Sumo wrestlers in the horizontal direction and then determine the acceleration of the wrestler on the right once he's pushed.

Step 1: Labeling the Forces

To achieve a net force of 300 N to the right, we need to consider the forces acting on both wrestlers.

Let's denote the force exerted by the wrestler on the left as \( F_{\text{left}} \) and the force exerted by the wrestler on the right as \( F_{\text{right}} \).

To have a net force of 300 N to the right:

• The force exerted by the wrestler on the right must be greater than the force exerted by the wrestler on the left.

Therefore, we can label the forces as follows:

• \( F_{\text{right}} = F_{\text{left}} + 300 \text{ N} \)

For example, if we label:

• \( F_{\text{left}} = 400 \text{ N} \) (acting to the left)
• \( F_{\text{right}} = 700 \text{ N} \) (acting to the right)

The net force would be: \[ \text{Net Force} = F_{\text{right}} - F_{\text{left}} = 700 \text{ N} - 400 \text{ N} = 300 \text{ N} \text{ (to the right)} \]

Step 2: Calculating the Acceleration of the Flying Sumo Wrestler

Now that we have the net force when the right wrestler is pushed out, we can calculate the acceleration using Newton's second law, \( F = ma \):

Given:

• Net Force (\( F \)) = 300 N (to the right)
• Mass of the wrestler (\( m \)) = 150 kg

Using the formula: \[ a = \frac{F}{m} = \frac{300 \text{ N}}{150 \text{ kg}} = 2 \text{ m/s}^2 \]

Summary:

1. Forces in the horizontal direction:

   • \( F_{\text{left}} = 400 \text{ N} \) (left)
   • \( F_{\text{right}} = 700 \text{ N} \) (right)

2. The acceleration of the flying Sumo wrestler is:

   • \( a = 2 \text{ m/s}^2 \) (to the right)

You can arrange the forces and write the acceleration in the way indicated in your task!