A toy helicopter flies forward with a force of 15 N into an oncoming wind of 10 N. The force ofgravity pulls the helicopter down with a force of 5 N, but the propeller is providing an upwardforce of 10 N.

To determine the net forces acting on the toy helicopter, we need to consider both the forward forces and the vertical forces.

1. Forward Forces:

   • The helicopter has a forward thrust of 15 N.
   • There is an opposing wind force of 10 N.

   Therefore, the net forward force is: \[ \text{Net Forward Force} = \text{Thrust} - \text{Wind} = 15 , \text{N} - 10 , \text{N} = 5 , \text{N} \]

2. Vertical Forces:

   • The propeller provides an upward force of 10 N.
   • Gravity pulls the helicopter down with a force of 5 N.

   Therefore, the net upward force is: \[ \text{Net Upward Force} = \text{Upward Force} - \text{Gravity} = 10 , \text{N} - 5 , \text{N} = 5 , \text{N} \]

Putting this information together:

• The toy helicopter is flying forward with a net force of 5 N.
• The toy helicopter is flying upward with a net force of 5 N.

So, the correct answer is: The toy helicopter is flying forward with a force of 5 N and upward with a force of 5 N.