Two movers are attempting to push a couch up a ramp. One mover applies a force of 80 N tothe right, but the force of friction between the couch and the ramp is providing a force of 110 Nin the opposite direction, and the couch slides down the ramp.

To determine the minimum force that the second mover needs to apply to help push the couch up the ramp, we need to consider the forces acting on the couch.

Currently, one mover is applying a force of 80 N to the right (up the ramp), while the force of friction is 110 N acting to the left (down the ramp).

Net force acting on the couch before the second mover applies any force:

\[ \text{Net Force} = \text{Force Up} - \text{Force Down} \]

\[ \text{Net Force} = 80 , \text{N} - 110 , \text{N} = -30 , \text{N} \]

The negative sign indicates that the couch is sliding down the ramp.

To start moving the couch up the ramp, the total force (the force from both movers) must overcome the friction force. The friction force is 110 N, so the total force required to just overcome the friction is:

\[ \text{Force required} = 110 , \text{N} \]

Currently, one mover is providing 80 N. Therefore, the second mover needs to apply an additional force:

\[ \text{Force from second mover} = \text{Force required} - \text{Force from first mover} \]

\[ \text{Force from second mover} = 110 , \text{N} - 80 , \text{N} = 30 , \text{N} \]

Thus, the second mover needs to apply at least 30 N to help push the couch up the ramp.

The correct answer is 30 N.