Use the equation for motion to answer the question.

To find the final position of the object after 1 second using the equation for motion \( x = x_0 + v_0t + \frac{1}{2}at^2 \), we need to identify the values of the variables:

• \( x_0 = 2 \) m (starting position)
• \( v_0 = 15 \) m/s (starting velocity)
• \( a = 0 \) m/s² (since the object is moving at a constant speed, acceleration is zero)
• \( t = 1 \) s (time)

Now, we can plug these values into the equation: \[ x = x_0 + v_0t + \frac{1}{2}at^2 \] Substituting the values: \[ x = 2 , \text{m} + (15 , \text{m/s} \cdot 1 , \text{s}) + \frac{1}{2}(0)\cdot(1)^2 \] \[ x = 2 , \text{m} + 15 , \text{m} + 0 \] \[ x = 17 , \text{m} \]

The final position of the object after 1 second is 17 m.