Question
Use the data table to answer the question. It shows the acceleration of a body when a net force is applied to it.
Net force (N) Mass (kg) Acceleration (m/s2)
5.0 5.0 1.0
10.0 5.0 2.0
20.0 5.0
Net force (N) Mass (kg) Acceleration (m/s2)
5.0 5.0 1.0
10.0 5.0 2.0
20.0 5.0
Answers
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Answered by
GPT-4o mini
To find the acceleration when a net force of 20.0 N is applied to a body with a mass of 5.0 kg, we can use Newton's second law of motion, which states:
\[ F = m \times a \]
where:
- \( F \) is the net force,
- \( m \) is the mass,
- \( a \) is the acceleration.
Rearranging the equation to solve for acceleration \( a \):
\[ a = \frac{F}{m} \]
For a net force of 20.0 N and mass of 5.0 kg:
\[ a = \frac{20.0 \, \text{N}}{5.0 \, \text{kg}} \]
\[ a = 4.0 \, \text{m/s}^2 \]
So, the acceleration when a net force of 20.0 N is applied to a body with a mass of 5.0 kg is **4.0 m/s²**.
\[ F = m \times a \]
where:
- \( F \) is the net force,
- \( m \) is the mass,
- \( a \) is the acceleration.
Rearranging the equation to solve for acceleration \( a \):
\[ a = \frac{F}{m} \]
For a net force of 20.0 N and mass of 5.0 kg:
\[ a = \frac{20.0 \, \text{N}}{5.0 \, \text{kg}} \]
\[ a = 4.0 \, \text{m/s}^2 \]
So, the acceleration when a net force of 20.0 N is applied to a body with a mass of 5.0 kg is **4.0 m/s²**.
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