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The volume of a sphere is 48 m3. What is the volume of a cylinder if its radius is the same as the sphere’s and its height is e...Question
The volume of a sphere is 72 m3
. What is the volume of a cone if its radius is the same as the sphere’s and its height is equal to the sphere’s diameter?
. What is the volume of a cone if its radius is the same as the sphere’s and its height is equal to the sphere’s diameter?
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Answered by
GPT-4o mini
To find the volume of a cone with the same radius as a sphere and a height equal to the sphere's diameter, we first need to determine the radius of the sphere from its given volume.
The formula for the volume \( V \) of a sphere is:
\[
V = \frac{4}{3} \pi r^3
\]
Given that the volume of the sphere is \( 72 \, \text{m}^3 \), we can set up the equation:
\[
\frac{4}{3} \pi r^3 = 72
\]
To solve for \( r^3 \), we will multiply both sides by \( \frac{3}{4\pi} \):
\[
r^3 = \frac{72 \cdot 3}{4\pi} = \frac{216}{4\pi} = \frac{54}{\pi}
\]
Now, we need to find \( r \):
\[
r = \left(\frac{54}{\pi}\right)^{1/3}
\]
Next, we calculate the diameter of the sphere, which is:
\[
\text{Diameter} = 2r = 2 \left(\frac{54}{\pi}\right)^{1/3}
\]
Now that we have established the radius and height of the cone, we can use the formula for the volume \( V \) of a cone:
\[
V = \frac{1}{3} \pi r^2 h
\]
Here, \( h = 2r \). Substituting this into the formula gives:
\[
V = \frac{1}{3} \pi r^2 (2r) = \frac{2}{3} \pi r^3
\]
Now, we can substitute \( r^3 \) (which we found earlier):
\[
V = \frac{2}{3} \pi \left(\frac{54}{\pi}\right)
\]
This simplifies to:
\[
V = \frac{2 \cdot 54}{3} = \frac{108}{3} = 36 \, \text{m}^3
\]
Thus, the volume of the cone is:
\[
\boxed{36 \, \text{m}^3}
\]
The formula for the volume \( V \) of a sphere is:
\[
V = \frac{4}{3} \pi r^3
\]
Given that the volume of the sphere is \( 72 \, \text{m}^3 \), we can set up the equation:
\[
\frac{4}{3} \pi r^3 = 72
\]
To solve for \( r^3 \), we will multiply both sides by \( \frac{3}{4\pi} \):
\[
r^3 = \frac{72 \cdot 3}{4\pi} = \frac{216}{4\pi} = \frac{54}{\pi}
\]
Now, we need to find \( r \):
\[
r = \left(\frac{54}{\pi}\right)^{1/3}
\]
Next, we calculate the diameter of the sphere, which is:
\[
\text{Diameter} = 2r = 2 \left(\frac{54}{\pi}\right)^{1/3}
\]
Now that we have established the radius and height of the cone, we can use the formula for the volume \( V \) of a cone:
\[
V = \frac{1}{3} \pi r^2 h
\]
Here, \( h = 2r \). Substituting this into the formula gives:
\[
V = \frac{1}{3} \pi r^2 (2r) = \frac{2}{3} \pi r^3
\]
Now, we can substitute \( r^3 \) (which we found earlier):
\[
V = \frac{2}{3} \pi \left(\frac{54}{\pi}\right)
\]
This simplifies to:
\[
V = \frac{2 \cdot 54}{3} = \frac{108}{3} = 36 \, \text{m}^3
\]
Thus, the volume of the cone is:
\[
\boxed{36 \, \text{m}^3}
\]
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