First, let's compute the product of \( \frac{1}{2} \) and \( \frac{5}{7} \):
\[ \frac{1}{2} \times \frac{5}{7} = \frac{1 \times 5}{2 \times 7} = \frac{5}{14} \]
Now, we compare \( \frac{5}{14} \) with \( \frac{1}{2} \).
To compare \( \frac{5}{14} \) and \( \frac{1}{2} \), we can find a common denominator or convert \( \frac{1}{2} \) to have the same denominator as \( \frac{5}{14} \).
The denominator of \( \frac{1}{2} \) is 2, and we can convert it to a denominator of 14:
\[ \frac{1}{2} = \frac{1 \times 7}{2 \times 7} = \frac{7}{14} \]
Now we have:
- \( \frac{5}{14} \)
- \( \frac{7}{14} \)
Now we can compare:
\[ \frac{5}{14} < \frac{7}{14} \]
Thus, the comparison statement \( \frac{5}{14} \) \( \frac{1}{2} \) can be completed as:
\[ \frac{5}{14} < \frac{1}{2} \]
Therefore, the answer is "<".