Question
4.
The table shows the points of a function. Complete the table to show the points after a reflection about the origin.
x f(x)
-4 8
-3 2
-2 0
-1 2
0 8
(5 points)
Complete the table to show that h(x)
is the reflection about the origin of the function f(x)
x h(x)
4
3
2
1
0
The table shows the points of a function. Complete the table to show the points after a reflection about the origin.
x f(x)
-4 8
-3 2
-2 0
-1 2
0 8
(5 points)
Complete the table to show that h(x)
is the reflection about the origin of the function f(x)
x h(x)
4
3
2
1
0
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To reflect a point \((x, f(x))\) about the origin, we transform it to the point \((-x, -f(x))\).
Starting with the given points:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-4 & 8 \\
-3 & 2 \\
-2 & 0 \\
-1 & 2 \\
0 & 8 \\
\hline
\end{array}
\]
We need to find \( h(x) \) for corresponding positive \( x \) values:
1. For \( x = 4 \) (which reflects to \( -4 \)):
\( h(4) = -f(-4) = -8 \)
2. For \( x = 3 \) (which reflects to \( -3 \)):
\( h(3) = -f(-3) = -2 \)
3. For \( x = 2 \) (which reflects to \( -2 \)):
\( h(2) = -f(-2) = -0 = 0 \)
4. For \( x = 1 \) (which reflects to \( -1 \)):
\( h(1) = -f(-1) = -2 \)
5. For \( x = 0 \):
Since reflecting at zero keeps it the same, \( h(0) = -f(0) = -8 \)
Now we can populate the table:
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
4 & -8 \\
3 & -2 \\
2 & 0 \\
1 & -2 \\
0 & -8 \\
\hline
\end{array}
\]
Thus, the completed table showing the reflection about the origin is:
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
4 & -8 \\
3 & -2 \\
2 & 0 \\
1 & -2 \\
0 & -8 \\
\hline
\end{array}
\]
Starting with the given points:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-4 & 8 \\
-3 & 2 \\
-2 & 0 \\
-1 & 2 \\
0 & 8 \\
\hline
\end{array}
\]
We need to find \( h(x) \) for corresponding positive \( x \) values:
1. For \( x = 4 \) (which reflects to \( -4 \)):
\( h(4) = -f(-4) = -8 \)
2. For \( x = 3 \) (which reflects to \( -3 \)):
\( h(3) = -f(-3) = -2 \)
3. For \( x = 2 \) (which reflects to \( -2 \)):
\( h(2) = -f(-2) = -0 = 0 \)
4. For \( x = 1 \) (which reflects to \( -1 \)):
\( h(1) = -f(-1) = -2 \)
5. For \( x = 0 \):
Since reflecting at zero keeps it the same, \( h(0) = -f(0) = -8 \)
Now we can populate the table:
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
4 & -8 \\
3 & -2 \\
2 & 0 \\
1 & -2 \\
0 & -8 \\
\hline
\end{array}
\]
Thus, the completed table showing the reflection about the origin is:
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
4 & -8 \\
3 & -2 \\
2 & 0 \\
1 & -2 \\
0 & -8 \\
\hline
\end{array}
\]
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