According to the Law of Conservation of Mass, if 88 g of carbon dioxide (CO2

) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen (O2
) in the reactants?(1 point)
Responses

24 g
24 g

32 g
32 g

64 g
64 g

104 g

1 answer

To determine the mass of dioxygen (O2) in the reactants according to the Law of Conservation of Mass, we first need to calculate the total mass of the reactants based on the mass of the products.

According to the Law of Conservation of Mass, the mass of the reactants must equal the mass of the products.

We know that:

  • The mass of carbon (C) used = 24 g
  • The mass of carbon dioxide (CO2) produced = 88 g

Now, we can set up the equation based on the conservation of mass:

\[ \text{Mass of reactants} = \text{Mass of products} \]

The mass of the reactants (which includes carbon and dioxygen) can be expressed as:

\[ \text{Mass of C} + \text{Mass of O2} = \text{Mass of CO2} \]

Substituting the known values:

\[ 24 \text{ g (C)} + \text{Mass of O2} = 88 \text{ g (CO2)} \]

Now solve for the mass of dioxygen (O2):

\[ \text{Mass of O2} = 88 \text{ g} - 24 \text{ g} \] \[ \text{Mass of O2} = 64 \text{ g} \]

Thus, the mass of dioxygen (O2) in the reactants is 64 g.