4 x 10^-2 + 1.3 x 10^-1

Answer 1

To add the two numbers $4\times {10}^{-2}$ and $1.3\times {10}^{-1}$, we first need to express them with the same exponent.

1. Convert $1.3\times {10}^{-1}$ to have the same exponent as $4\times {10}^{-2}$: $$1.3\times {10}^{-1}=1.3\times {10}^{-1}=1.3\times {10}^{-1}\times \frac{10}{10}=13\times {10}^{-2}$$

2. Now we can add $4\times {10}^{-2}$ and $13\times {10}^{-2}$: $$4\times {10}^{-2}+13\times {10}^{-2}=(4+13)\times {10}^{-2}=17\times {10}^{-2}$$

3. Finally, we can rewrite $17\times {10}^{-2}$ in standard form: $$17\times {10}^{-2}=0.17$$

So, $4\times {10}^{-2}+1.3\times {10}^{-1}=0.17$.

Answer 2

express your answer to 1 decimal place

Answer 3

The result we found was $0.17$. When rounded to one decimal place, it becomes $0.2$.

So, the final answer expressed to one decimal place is $0.2$.

Answer 4

wrong

Answer 5

I apologize for the confusion. Let's clarify:

The original summation was:

$$4\times {10}^{-2}+1.3\times {10}^{-1}$$

Calculating it step by step:

1. Convert $1.3\times {10}^{-1}$ to the same exponent as $4\times {10}^{-2}$: $$1.3\times {10}^{-1}=13\times {10}^{-2}$$

2. Now, perform the addition: $$4\times {10}^{-2}+13\times {10}^{-2}=(4+13)\times {10}^{-2}=17\times {10}^{-2}$$

3. Convert to decimal form: $$17\times {10}^{-2}=0.17$$

Now, when we round $0.17$ to one decimal place, we look at the digit in the second decimal place (which is 7) to decide whether to round up or not. Since it is 5 or more, we round up.

Thus: $$0.17\text{ rounded to one decimal place is }0.2$$

If I made an error in interpreting your request or if you meant something else, please let me know!