What is the common ratio in the following geometric sequence?

2, 1/2, 1/8, 1/32

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the common ratio of a geometric sequence, you divide any term by the previous term.

Let's calculate the common ratio \( r \) using the first and second terms:

\[ r = \frac{\text{second term}}{\text{first term}} = \frac{1/2}{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \]

Now let's check the ratio between the second and third terms:

\[ r = \frac{\text{third term}}{\text{second term}} = \frac{1/8}{1/2} = \frac{1/8}{1/2} = \frac{1}{8} \times \frac{2}{1} = \frac{2}{8} = \frac{1}{4} \]

And let's check the ratio between the third and fourth terms:

\[ r = \frac{\text{fourth term}}{\text{third term}} = \frac{1/32}{1/8} = \frac{1/32}{1/8} = \frac{1}{32} \times \frac{8}{1} = \frac{8}{32} = \frac{1}{4} \]

Since the common ratio is the same for all pairs of consecutive terms, we can conclude that the common ratio of the geometric sequence \( 2, 1/2, 1/8, 1/32 \) is

\[ \boxed{\frac{1}{4}}. \]