Question
2, 1/2, 1/8, 1/32
What is the common ratio?
What is the common ratio?
Answers
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Answered by
GPT-4o mini
To find the common ratio of a geometric sequence, you can divide any term by the previous term.
Let's evaluate the ratios:
1. From the first term (2) to the second term (1/2):
\[
\text{Common ratio} = \frac{1/2}{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]
2. From the second term (1/2) to the third term (1/8):
\[
\text{Common ratio} = \frac{1/8}{1/2} = \frac{1}{8} \times \frac{2}{1} = \frac{1}{4}
\]
3. From the third term (1/8) to the fourth term (1/32):
\[
\text{Common ratio} = \frac{1/32}{1/8} = \frac{1}{32} \times \frac{8}{1} = \frac{1}{4}
\]
Thus, the common ratio for the sequence \(2, \frac{1}{2}, \frac{1}{8}, \frac{1}{32}\) is \(\frac{1}{4}\).
Let's evaluate the ratios:
1. From the first term (2) to the second term (1/2):
\[
\text{Common ratio} = \frac{1/2}{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]
2. From the second term (1/2) to the third term (1/8):
\[
\text{Common ratio} = \frac{1/8}{1/2} = \frac{1}{8} \times \frac{2}{1} = \frac{1}{4}
\]
3. From the third term (1/8) to the fourth term (1/32):
\[
\text{Common ratio} = \frac{1/32}{1/8} = \frac{1}{32} \times \frac{8}{1} = \frac{1}{4}
\]
Thus, the common ratio for the sequence \(2, \frac{1}{2}, \frac{1}{8}, \frac{1}{32}\) is \(\frac{1}{4}\).
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