To transform the function \( f(x) = 3x \) into \( -f(3x - 2) + 1 \), we can break it down into a series of operations. Let's go through the transformations step by step:
- Start with \( f(x) = 3x \).
- Substitute \( 3x - 2 \) into \( f \): This gives us \( f(3x - 2) = 3(3x - 2) \).
- Multiply by -1: We then take the negative of the function, yielding \( -f(3x - 2) = -3(3x - 2) \).
- Add 1: Finally, we add 1 to the function, obtaining \( -3(3x - 2) + 1 \).
Now let's fill out the table based on these operations:
| Step | Expression | Value of Expression for \( x \) | |--------------------------------------------------|------------------------------------|--------------------------------------| | 1. Start with the original function | \( f(x) = 3x \) | \( 3x \) | | 2. Substitute \( 3x - 2 \) | \( f(3x - 2) = 3(3x - 2) \) | \( 3(3x - 2) \) | | 3. Apply negative function | \( -f(3x - 2) = -3(3x - 2) \) | \( -3(3x - 2) \) | | 4. Add 1 to the function | \( -3(3x - 2) + 1 \) | \( -3(3x - 2) + 1 \) | | Final expression | Complete transformation: | \( -3(3x - 2) + 1 \) |
To summarize:
- Step 1 starts with \( f(x) = 3x \)
- Step 2 replaces \( x \) with \( 3x - 2 \)
- Step 3 negates the value of the function
- Step 4 adds 1 to the result to complete the transformation into \( -f(3x - 2) + 1 \)
Please evaluate \( 3x \), \( f(3x - 2) \), and \( -f(3x - 2) + 1 \) for specific values of \( x \) if needed.