To find how much Mr. Brown will make after teaching for 3, 4, and 5 years, we can substitute the values of \(y\) into the function \(s = 1,500y + 40,000\).
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For \(y = 3\): \[ s = 1,500(3) + 40,000 = 4,500 + 40,000 = 44,500 \] So for 3 years, Mr. Brown will make \(44,500\).
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For \(y = 4\): \[ s = 1,500(4) + 40,000 = 6,000 + 40,000 = 46,000 \] So for 4 years, Mr. Brown will make \(46,000\).
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For \(y = 5\): \[ s = 1,500(5) + 40,000 = 7,500 + 40,000 = 47,500 \] So for 5 years, Mr. Brown will make \(47,500\).
Now we can summarize the results:
- After 3 years: \( (3, 44,500) \)
- After 4 years: \( (4, 46,000) \)
- After 5 years: \( (5, 47,500) \)
The correct answer is: (3, 44,500), (4, 46,000), and (5, 47,500).