To divide \( 8 \frac{1}{1} \) (which is equivalent to \( 8 + 1 = 9 \)) by \( 1 \frac{2}{1} \) (equivalent to \( 1 + 2 = 3 \)), we first need to express \( 1 \frac{2}{1} \) as an improper fraction.
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Convert Mixed Numbers to Improper Fractions:
- \( 8 \frac{1}{1} = \frac{9}{1} \)
- \( 1 \frac{2}{1} = \frac{3}{1} \)
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To Divide Two Fractions:
- When dividing by a fraction, multiply by its reciprocal.
- So, \( \frac{9}{1} \div \frac{3}{1} = \frac{9}{1} \times \frac{1}{3} \)
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Multiply the Fractions:
- \( \frac{9}{1} \times \frac{1}{3} = \frac{9 \times 1}{1 \times 3} = \frac{9}{3} \)
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Simplify the Fraction:
- \( \frac{9}{3} = 3 \)
Therefore, the answer to the problem \( 8 \frac{1}{1} \div 1 \frac{2}{1} \) is \( 3 \).
Thus, your division looks like this: \[ 8 \frac{1}{1} \div 1 \frac{2}{1} = \frac{9}{1} \div \frac{3}{1} = \frac{9}{3} = 3 \]