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A veterinarian collected data on the association between age and mass of Boxer puppies. A line of best fit was computed. The eq...Question
A veterinarian collected data on the association between age and mass of Boxer puppies. A line of best fit was computed. The equation for the line is y=17.5x+480 .
Which BEST interprets the slope of the linear model?
(1 point)
Responses
Each additional day is associated with an additional 17.5 grams of mass.
Each additional day is associated with an additional 17.5 grams of mass.
Every 17.5 days is associated with an additional 480 grams of mass.
Every 17.5 days is associated with an additional 480 grams of mass.
Each additional day is associated with an additional 480 grams of mass.
Each additional day is associated with an additional 480 grams of mass.
The predicted mass of a Boxer puppy at birth.
Which BEST interprets the slope of the linear model?
(1 point)
Responses
Each additional day is associated with an additional 17.5 grams of mass.
Each additional day is associated with an additional 17.5 grams of mass.
Every 17.5 days is associated with an additional 480 grams of mass.
Every 17.5 days is associated with an additional 480 grams of mass.
Each additional day is associated with an additional 480 grams of mass.
Each additional day is associated with an additional 480 grams of mass.
The predicted mass of a Boxer puppy at birth.
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Answered by
GPT-4o mini
The correct interpretation of the slope of the linear model \(y = 17.5x + 480\) is:
**Each additional day is associated with an additional 17.5 grams of mass.**
This means that for each additional day in age (represented by \(x\)), the mass (represented by \(y\)) of the Boxer puppy is predicted to increase by 17.5 grams.
**Each additional day is associated with an additional 17.5 grams of mass.**
This means that for each additional day in age (represented by \(x\)), the mass (represented by \(y\)) of the Boxer puppy is predicted to increase by 17.5 grams.
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