Question

Use the table to answer the question.

0 350
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A certain population of beetles is increasing at a rate of 22% per month. If there are currently 350 beetles, the equation f(x)=350(1.22)x
can be used to model the situation. Finish the chart and plot the points to determine which graph correctly displays the situation.(1 point)
Responses

An increasing curve with an arrow on the top is plotted on a coordinate plane. The x-axis for months ranges from 0 to 2,000 in increments of 200. The y-axis for Beetles ranges from 0 to 10 in increments of 1.
Image with alt text: An increasing curve with an arrow on the top is plotted on a coordinate plane. The x-axis for months ranges from 0 to 2,000 in increments of 200. The y-axis for Beetles ranges from 0 to 10 in increments of 1.

A decreasing curve with an arrow at the end is plotted on a coordinate plane. The x-axis for months ranges from 0 to 10 in increments of 1. The y-axis for Beetles ranges from 0 to 350 in increments of 50.
Image with alt text: A decreasing curve with an arrow at the end is plotted on a coordinate plane. The x-axis for months ranges from 0 to 10 in increments of 1. The y-axis for Beetles ranges from 0 to 350 in increments of 50.

An increasing curve with an arrow on the top is plotted on a coordinate plane. The x-axis for months ranges from 0 to 10 in increments of 1. The y-axis for Beetles ranges from 0 to 2000 in increments of 250.
Image with alt text: An increasing curve with an arrow on the top is plotted on a coordinate plane. The x-axis for months ranges from 0 to 10 in increments of 1. The y-axis for Beetles ranges from 0 to 2000 in increments of 250.

A decreasing curve with an arrow at the end is plotted on a coordinate plane. The x-axis for months ranges from 0 to 10 in increments of 1. The y-axis for Beetles ranges from 0 to 350 in increments of 50.
Image with alt text: A decreasing curve with an arrow at the end is plotted on a coordinate plane. The x-axis for months ranges from 0 to 10 in increments of 1. The y-axis for Beetles ranges from 0 to 350 in increments of 50.
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User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
3 hours ago

To solve the population growth of the beetles, we apply the formula:

\[ f(x) = 350(1.22)^x \]

where:

  • \( f(x) \) represents the population after \( x \) months,
  • \( 350 \) is the initial population,
  • \( 1.22 \) represents the 22% increase per month.

We can compute the population for the first few months (from \( x = 0 \) to \( x = 5 \)):

  1. For \( x = 0 \): \[ f(0) = 350(1.22)^0 = 350 \]

  2. For \( x = 1 \): \[ f(1) = 350(1.22)^1 = 350 \times 1.22 = 427 \]

  3. For \( x = 2 \): \[ f(2) = 350(1.22)^2 = 350 \times 1.4884 \approx 520 \]

  4. For \( x = 3 \): \[ f(3) = 350(1.22)^3 = 350 \times 1.8147 \approx 634 \]

  5. For \( x = 4 \): \[ f(4) = 350(1.22)^4 = 350 \times 2.2090 \approx 772 \]

  6. For \( x = 5 \): \[ f(5) = 350(1.22)^5 = 350 \times 2.6880 \approx 941 \]

Putting this data into a chart, we have:

| Months (x) | Population (f(x)) | |------------|---------------------| | 0 | 350 | | 1 | 427 | | 2 | 520 | | 3 | 634 | | 4 | 772 | | 5 | 941 |

Now, let's plot these points on a graph. From the table, we can see that the population is increasing, hence the graph should be an increasing curve.

Given the descriptions of the graphs:

  • The first graph describes an increasing curve.
  • The second and fourth graphs depict decreasing curves.
  • The third graph also describes an increasing curve but is much larger in scale.

Considering the computed values (especially for smaller values of \( x \)), the first graph matches the increasing trend and lower scale of the beetle population, unlike the third graph which has a different range.

Therefore, the correct graph that displays the situation is the first one: an increasing curve with an arrow at the top.