Use long division to find the quotient.

(6x^4-11x^3-7x^2+8x+3)/(3x+2)





A
2x3−5x2+x+12x^3-5x^2+x+12x
3
−5x
2
+x+1

B
2x3−5x2+x+2−13x+22x^3-5x^2+x+2-\frac{1}{3x+2}2x
3
−5x
2
+x+2−
3x+2
1



C
2x3−5x2+x+22x^3-5x^2+x+22x
3
−5x
2
+x+2

D
2x3−5x2+x+2+13x+22x^3-5x^2+x+2+\frac{1}{3x+2}2x
3
−5x
2
+x+2+
3x+2
1

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
3 hours ago

To perform polynomial long division for the expression \((6x^4 - 11x^3 - 7x^2 + 8x + 3) \div (3x + 2)\), follow these steps:

  1. Divide the leading term of the dividend \(6x^4\) by the leading term of the divisor \(3x\): \[ \frac{6x^4}{3x} = 2x^3. \]

  2. Multiply \(2x^3\) by the entire divisor \(3x + 2\): \[ 2x^3 \cdot (3x + 2) = 6x^4 + 4x^3. \]

  3. Subtract this result from the original polynomial: \[ (6x^4 - 11x^3 - 7x^2 + 8x + 3) - (6x^4 + 4x^3) = -15x^3 - 7x^2 + 8x + 3. \]

  4. Bring down the next term and repeat the process. Divide \(-15x^3\) by \(3x\): \[ \frac{-15x^3}{3x} = -5x^2. \]

  5. Multiply \(-5x^2\) by \(3x + 2\): \[ -5x^2 \cdot (3x + 2) = -15x^3 - 10x^2. \]

  6. Subtract this from the current polynomial: \[ (-15x^3 - 7x^2 + 8x + 3) - (-15x^3 - 10x^2) = 3x^2 + 8x + 3. \]

  7. Now divide \(3x^2\) by \(3x\): \[ \frac{3x^2}{3x} = x. \]

  8. Multiply \(x\) by \(3x + 2\): \[ x \cdot (3x + 2) = 3x^2 + 2x. \]

  9. Subtract: \[ (3x^2 + 8x + 3) - (3x^2 + 2x) = 6x + 3. \]

  10. Now divide \(6x\) by \(3x\): \[ \frac{6x}{3x} = 2. \]

  11. Multiply: \[ 2 \cdot (3x + 2) = 6x + 4. \]

  12. Subtract: \[ (6x + 3) - (6x + 4) = -1. \]

So the final result of the division is: \[ 2x^3 - 5x^2 + x + 2 - \frac{1}{3x + 2}. \]

In this context, the correct answer using the choices provided would be: \[ \text{Option B: } 2x^3 - 5x^2 + x + 2 - \frac{1}{3x + 2}. \]