What is the remainder when

x
3
+
3
x
2

10
x

14
x
3
+3x
2
−10x−14 is divided by
x

3
x−3?

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
3 hours ago

To find the remainder when the polynomial \( x^3 + 3x^2 - 10x - 14 \) is divided by \( x - 3 \), we can use the Remainder Theorem. The Remainder Theorem states that the remainder of the polynomial \( f(x) \) when divided by \( x - c \) is \( f(c) \).

In this case, our polynomial is

\[ f(x) = x^3 + 3x^2 - 10x - 14 \]

We need to find \( f(3) \):

\[ f(3) = 3^3 + 3(3^2) - 10(3) - 14 \]

Calculating each term:

\[ 3^3 = 27 \] \[ 3(3^2) = 3(9) = 27 \] \[ -10(3) = -30 \]

Now substituting these values into \( f(3) \):

\[ f(3) = 27 + 27 - 30 - 14 \]

Now, perform the additions and subtractions:

\[ 27 + 27 = 54 \] \[ 54 - 30 = 24 \] \[ 24 - 14 = 10 \]

Thus, the remainder when \( x^3 + 3x^2 - 10x - 14 \) is divided by \( x - 3 \) is

\[ \boxed{10} \]