Divide using synthetic division. Write your answer in standard form.

(
5
x
4
+
12
x
3

21
x
2

40
x

12
)

÷

(
x
+
3
)
(5x
4
+12x
3
−21x
2
−40x−12) ÷ (x+3)

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To perform synthetic division of the polynomial \( 5x^4 + 12x^3 - 21x^2 - 40x - 12 \) by \( x + 3 \), we will use the root of \( x + 3 \), which is \( -3 \).

  1. Set up the synthetic division:

    • Write the coefficients of the polynomial: \( 5, 12, -21, -40, -12 \).
    • Use \( -3 \) as the divisor.
  2. Synthetic division steps:

    • Write down the coefficients:

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & & & & \ \end{array} \]

    • Bring down the leading coefficient (5):

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & & & & \ & 5 & & & & \ \end{array} \]

    • Multiply \( 5 \) by \( -3 \) and write the result under the next coefficient:

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & -15 & & & \ & 5 & & & & \ \end{array} \]

    • Add the second column:

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & -15 & & & \ & 5 & -3 & & & \ \end{array} \]

    • Continue this process:

    \[ -3 \times -3 = 9 \quad \text{(add to -21:)} \quad -21 + 9 = -12 \]

    • Continue this:

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & -15 & 9 & & \ & 5 & -3 & -12 & & \ \end{array} \]

    • Multiply \( -12 \) by \( -3 \):

    \[ -12 \times -3 = 36 \]

    • Add to -40:

    \[ -40 + 36 = -4 \]

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & -15 & 9 & 36 & \ & 5 & -3 & -12 & -4 & \ \end{array} \]

    • Finally, multiply \( -4 \) by \( -3 \):

    \[ -4 \times -3 = 12 \]

    • Add to -12:

    \[ -12 + 12 = 0 \]

  3. Complete synthetic division:

    The synthetic division is complete:

    \[ \begin{array}{r|rrrrr} -3 & 5 & 12 & -21 & -40 & -12 \ & & -15 & 9 & 36 & 12 \ & 5 & -3 & -12 & -4 & 0 \ \end{array} \]

    • The result of the synthetic division is \( 5x^3 - 3x^2 - 12x - 4 \) (with a remainder of 0).
  4. Write the answer in standard form:

    Thus, the solution to the division of \( 5x^4 + 12x^3 - 21x^2 - 40x - 12 \) by \( x + 3 \) is:

    \[ 5x^3 - 3x^2 - 12x - 4 \]