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A water tower has a height of 25 meters and a width of 16 meters. What is the volume of the water tower?Asked by brant
A water tower has a height of 25 meters and a width of 16 meters. What is the volume of the water tower? Use 3.14 for pi
Answers
Answered by
GPT-4o mini
To find the volume of the water tower, we first need to determine the shape of the tower. If we assume it is a cylindrical water tower (which is typical), the formula for the volume \( V \) of a cylinder is given by:
\[
V = \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height.
Given:
- The height \( h = 25 \) meters
- The width (diameter) = 16 meters, so the radius \( r \) is half of the diameter:
\[
r = \frac{16}{2} = 8 \text{ meters}
\]
Now we can plug the values into the volume formula:
\[
V = \pi (8)^2 (25)
\]
Calculating \( (8)^2 \):
\[
(8)^2 = 64
\]
Now plug this back into the volume formula:
\[
V = 3.14 \times 64 \times 25
\]
Now multiply \( 64 \times 25 \):
\[
64 \times 25 = 1600
\]
Now plug this back into the volume formula:
\[
V = 3.14 \times 1600
\]
Calculating \( 3.14 \times 1600 \):
\[
V = 5024
\]
Thus, the volume of the water tower is:
\[
\boxed{5024} \text{ cubic meters}
\]
\[
V = \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height.
Given:
- The height \( h = 25 \) meters
- The width (diameter) = 16 meters, so the radius \( r \) is half of the diameter:
\[
r = \frac{16}{2} = 8 \text{ meters}
\]
Now we can plug the values into the volume formula:
\[
V = \pi (8)^2 (25)
\]
Calculating \( (8)^2 \):
\[
(8)^2 = 64
\]
Now plug this back into the volume formula:
\[
V = 3.14 \times 64 \times 25
\]
Now multiply \( 64 \times 25 \):
\[
64 \times 25 = 1600
\]
Now plug this back into the volume formula:
\[
V = 3.14 \times 1600
\]
Calculating \( 3.14 \times 1600 \):
\[
V = 5024
\]
Thus, the volume of the water tower is:
\[
\boxed{5024} \text{ cubic meters}
\]
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