3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3

1 answer

The sum \(3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3\) consists of 25 occurrences of the number 3.

To find the total, you can multiply the number 3 by the number of occurrences:

\[ 3 \times 25 = 75 \]

So, the total is \(75\).