To solve the equation \( x^2 - 36 = 0 \) by factoring using the difference of squares pattern, we recognize that this can be rewritten as:
\[ x^2 - 6^2 = 0 \]
Using the difference of squares formula \( a^2 - b^2 = (a - b)(a + b) \), we can factor the equation as follows:
\[ (x - 6)(x + 6) = 0 \]
Setting each factor equal to zero gives us the solutions:
- \( x - 6 = 0 \) leads to \( x = 6 \)
- \( x + 6 = 0 \) leads to \( x = -6 \)
Therefore, the correct solutions are:
\[ x = 6 \quad \text{and} \quad x = -6 \]
This matches the option:
x=6, x=−6
x equals 6, x equals negative 6