Complete the square to solve the following quadratic equation: x^2−22x+1=15

x= -11 + 3√15, -11 -3√15
x=11+ 3√15, 11- 3√15
x=11+√14, 11 - √14
x= -11 √14, -11 -√14

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To solve the quadratic equation \( x^2 - 22x + 1 = 15 \) by completing the square, we first rewrite the equation in standard form:

\[ x^2 - 22x + 1 - 15 = 0 \]

This simplifies to:

\[ x^2 - 22x - 14 = 0 \]

Now, we will complete the square. Start by rearranging the equation:

\[ x^2 - 22x = 14 \]

Next, find the term to complete the square. Take half of the coefficient of \( x \) (which is \(-22\)), square it, and add it to both sides.

Half of \(-22\) is \(-11\), and squaring it gives \(121\):

\[ x^2 - 22x + 121 = 14 + 121 \]

This simplifies to:

\[ (x - 11)^2 = 135 \]

Next, take the square root of both sides:

\[ x - 11 = \pm \sqrt{135} \]

This further simplifies to:

\[ x - 11 = \pm 3\sqrt{15} \]

Therefore, we can isolate \( x \):

\[ x = 11 \pm 3\sqrt{15} \]

The solutions to the original equation are:

\[ x = 11 + 3\sqrt{15} \quad \text{and} \quad x = 11 - 3\sqrt{15} \]

Now, looking at the options you provided, the correct answer is:

\(x = 11 + 3\sqrt{15}, 11 - 3\sqrt{15}\)