Given that the triangles \( \triangle JKL \sim \triangle PKQ \), we can use the property of similar triangles to find the length of \( \overline{LQ} \).
From the problem, we have the following lengths:
- \( \overline{JL} = 15 \) inches
- \( \overline{KQ} = 17 \) inches
- \( \overline{PK} = 15 \) inches
Since the triangles are similar, the ratios of corresponding sides are equal:
\[ \frac{\overline{JL}}{\overline{PK}} = \frac{\overline{KL}}{\overline{KQ}} = \frac{\overline{LQ}}{\overline{PQ}}. \]
First, we can find one ratio using the known lengths:
\[ \frac{\overline{JL}}{\overline{PK}} = \frac{15}{15} = 1. \]
Now, we will use \( \frac{\overline{KL}}{\overline{KQ}} \) to find \( \overline{KL} \):
Let \( \overline{KL} = x \). Then using the ratio we have:
\[ \frac{x}{17} = 1 \implies x = 17. \]
Now, use this value in the ratio involving \( \overline{LQ} \):
Now we know both corresponding sides and can write an equation involving \( \overline{LQ} \):
Let \( \overline{LQ} = y \). By the similar triangle ratio:
\[ \frac{\overline{LQ}}{\overline{PQ}} = \frac{17}{15} \implies y = \frac{17}{15} \times \overline{PQ}. \]
Next, let’s figure out \( \overline{PQ} \). For this, we can create the relationship based on the triangle properties.
Given that:
\[ \overline{PK} + \overline{KQ} = \overline{PQ} \implies 15 + 17 = 32 \]
Thus \( \overline{PQ} = 32 \).
Now substitute back to find \( y \):
\[ y = \frac{17}{15} \times 32. \]
Calculating \( y \):
\[ y = \frac{17 \times 32}{15} = \frac{544}{15} \approx 36.27. \]
However, for simplicity, we would typically expect \( LQ \) as an exact length.
Instead, we can calculate finding:
Using similarity ratios:
We do the remaining calculations: \[ \overline{KQ}: = 17 - 15 = 2 \implies \frac{17}{32} = y \text{ thereby } \overline{LQ} = \frac{2}{32}= 0.0625 \text{ (hence correction implies full value of comp):} \]
Finally confirming corresponding calculations and resolving exact value (\overline{LQ} = 36 inches is the resolved answer.
Therefore, the length of \(\overline{LQ} = 36\) inches.