Question
What is the identity of a sample that has a volume of 1.96 cm3 and a mass of 17.6 g?
A.
copper
B.
lead
C.
silver
D.
zinc
A.
copper
B.
lead
C.
silver
D.
zinc
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the identity of the sample, we can calculate its density using the formula:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Given:
- Mass = 17.6 g
- Volume = 1.96 cm³
Now, let's calculate the density:
\[
\text{Density} = \frac{17.6 \, \text{g}}{1.96 \, \text{cm}^3} \approx 8.98 \, \text{g/cm}^3
\]
Now we can compare this density with the known densities of the materials listed:
- Copper: approximately 8.96 g/cm³
- Lead: approximately 11.34 g/cm³
- Silver: approximately 10.49 g/cm³
- Zinc: approximately 7.14 g/cm³
The calculated density of approximately 8.98 g/cm³ is very close to the density of copper (8.96 g/cm³).
Therefore, the identity of the sample is **A. copper**.
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Given:
- Mass = 17.6 g
- Volume = 1.96 cm³
Now, let's calculate the density:
\[
\text{Density} = \frac{17.6 \, \text{g}}{1.96 \, \text{cm}^3} \approx 8.98 \, \text{g/cm}^3
\]
Now we can compare this density with the known densities of the materials listed:
- Copper: approximately 8.96 g/cm³
- Lead: approximately 11.34 g/cm³
- Silver: approximately 10.49 g/cm³
- Zinc: approximately 7.14 g/cm³
The calculated density of approximately 8.98 g/cm³ is very close to the density of copper (8.96 g/cm³).
Therefore, the identity of the sample is **A. copper**.
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