What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?

A.
aluminum
B.
iron
C.
zinc
D.
gold

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To identify the sample, we need to calculate its density using the formula:

\[ \text{Density} = \frac{\text{mass}}{\text{volume}} \]

Given:

  • Mass = 249.8 g
  • Volume = 92.5 cm³

Now, let's calculate the density:

\[ \text{Density} = \frac{249.8 , \text{g}}{92.5 , \text{cm}^3} \approx 2.70 , \text{g/cm}^3 \]

Now, let's compare this calculated density with the known densities of the provided options:

  • Aluminum: ~2.70 g/cm³
  • Iron: ~7.87 g/cm³
  • Zinc: ~7.14 g/cm³
  • Gold: ~19.32 g/cm³

The calculated density of approximately 2.70 g/cm³ closely matches the density of aluminum.

Therefore, the identity of the sample is: A. aluminum.