Question

What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?
A.
aluminum
B.
iron
C.
zinc
D.
gold

Answer 1

To identify the sample, we need to calculate its density using the formula:

\[
\text{Density} = \frac{\text{mass}}{\text{volume}}
\]

Given:
- Mass = 249.8 g
- Volume = 92.5 cm³

Now, let's calculate the density:

\[
\text{Density} = \frac{249.8 \, \text{g}}{92.5 \, \text{cm}^3} \approx 2.70 \, \text{g/cm}^3
\]

Now, let's compare this calculated density with the known densities of the provided options:

- **Aluminum**: ~2.70 g/cm³
- **Iron**: ~7.87 g/cm³
- **Zinc**: ~7.14 g/cm³
- **Gold**: ~19.32 g/cm³

The calculated density of approximately 2.70 g/cm³ closely matches the density of aluminum.

Therefore, the identity of the sample is:
**A. aluminum**.