To find the length of the ramp that fits diagonally in the cage, we can use the formula for the diagonal \(d\) of a rectangular prism:
\[ d = \sqrt{l^2 + w^2 + h^2} \]
where:
- \(l\) is the length,
- \(w\) is the width, and
- \(h\) is the height.
In this case:
- \(l = 70\) cm,
- \(w = 35\) cm,
- \(h = 50\) cm.
Now, let's calculate the diagonal.
First, we square each dimension:
\[ l^2 = 70^2 = 4900 \] \[ w^2 = 35^2 = 1225 \] \[ h^2 = 50^2 = 2500 \]
Now, we add these values together:
\[ l^2 + w^2 + h^2 = 4900 + 1225 + 2500 = 8625 \]
Next, we take the square root of the total:
\[ d = \sqrt{8625} \approx 92.9 \text{ cm} \]
Therefore, the length of the ramp needed to fit diagonally in the cage is approximately 92.9 cm.