Object A has a charge of –1 Coulomb. At a given distance, the object with which charge would be most strongly attracted by object A?

The force of attraction or repulsion between two charged objects is described by Coulomb's Law, which states that the force \( F \) between two point charges \( q_1 \) and \( q_2 \) is given by the formula:

\[ F = k \frac{|q_1 q_2|}{r^2} \]

where:

• \( k \) is Coulomb's constant,
• \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and
• \( r \) is the distance between the charges.

In this case, Object A has a charge of -1 Coulomb (i.e., \( q_1 = -1 , C \)). Objects with positive charges will be attracted to Object A (while those with negative charges will be repelled). The attraction strength depends on the magnitude of the charges.

Let's analyze the options:

1. +1 C: Attracts with force \( F = k \frac{|(-1)(1)|}{r^2} = k \frac{1}{r^2} \).
2. –2 C: Repulses, so no attraction.
3. +2 C: Attracts with force \( F = k \frac{|(-1)(2)|}{r^2} = k \frac{2}{r^2} \).
4. –1 C: Repulses, so no attraction.

The most strongly attracted charge will be the one with the largest positive magnitude. Therefore, comparing the positive options:

• The +1 C charge produces a force of \( k \frac{1}{r^2} \).
• The +2 C charge produces a force of \( k \frac{2}{r^2} \).

Thus, the charge that would be most strongly attracted by Object A (–1 C) is +2 C.

How does the magnitude of the electrical charge on objects affect the electric force between them?

options:

As the charge increases, the force becomes more negative.
As the charge increases, the force becomes more negative.

As the charge increases, the force decreases in strength.
As the charge increases, the force decreases in strength.

As the charge increases, the force increases in strength.
As the charge increases, the force increases in strength.

As the charge increases, the force becomes more attractive.

To understand how the magnitude of the electrical charge on objects affects the electric force between them, we can refer to Coulomb's Law. According to Coulomb's Law, the force \( F \) between two charges is given by:

\[ F = k \frac{|q_1 q_2|}{r^2} \]

where:

• \( k \) is Coulomb's constant,
• \( q_1 \) and \( q_2 \) are the charges of the two objects,
• \( r \) is the distance between the charges.

Analysis of Choices:

1. As the charge increases, the force becomes more negative.

   • This statement is misleading; while the force can be attractive (negative in value if we consider direction), the magnitude of force is a positive quantity based on \( |q_1 q_2| \).

2. As the charge increases, the force decreases in strength.

   • This is incorrect. According to Coulomb's Law, if the charge increases, the force actually increases in strength.

3. As the charge increases, the force increases in strength.

   • This statement is correct. If either charge \( q_1 \) or charge \( q_2 \) increases in magnitude, the overall force \( F \) increases.

4. As the charge increases, the force becomes more attractive.

   • This statement is somewhat misleading. While increasing the magnitude of a positive charge will attract a negative charge more strongly, it does not apply in a broader sense (e.g., like charges repel).

Given these analyses, the best answer is:

As the charge increases, the force increases in strength.