Question
Use the table below to determine whether f(x) could represent a linear function. If it could, write f(x) in the form f(x)equals=mxplus+b.
x
minus−2
0
2
4
f(x)
1111
66
11
negative 4−4
Question content area bottom
Part 1
Select the correct choice and, if necessary, fill in the answer box in your choice below.
A.
The values could represent the linear function f(x)equals=enter your response here.
(Use integers or fractions for any numbers in the expression.)
B.
The function is not linear.
x
minus−2
0
2
4
f(x)
1111
66
11
negative 4−4
Question content area bottom
Part 1
Select the correct choice and, if necessary, fill in the answer box in your choice below.
A.
The values could represent the linear function f(x)equals=enter your response here.
(Use integers or fractions for any numbers in the expression.)
B.
The function is not linear.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine whether \( f(x) \) could represent a linear function, we can check if the differences in \( f(x) \) values are constant as \( x \) increases.
The given data points are:
\[
\begin{align*}
x: & \quad -2, \quad 0, \quad 2, \quad 4 \\
f(x): & \quad 11, \quad 6, \quad 11, \quad -4 \\
\end{align*}
\]
**Step 1: Calculate the differences in \( f(x) \)**
Let's find the values of \( f(x) \) for the successive pairs of \( x \):
- From \( x = -2 \) to \( x = 0 \):
\[
f(0) - f(-2) = 6 - 11 = -5
\]
- From \( x = 0 \) to \( x = 2 \):
\[
f(2) - f(0) = 11 - 6 = 5
\]
- From \( x = 2 \) to \( x = 4 \):
\[
f(4) - f(2) = -4 - 11 = -15
\]
**Step 2: Analyze the differences**
The differences in \( f(x) \) are not constant:
- The change from \( x = -2 \) to \( x = 0 \) is \( -5 \).
- The change from \( x = 0 \) to \( x = 2 \) is \( 5 \).
- The change from \( x = 2 \) to \( x = 4 \) is \( -15 \).
Since the differences are not consistent, \( f(x) \) does not represent a linear function.
**Conclusion:**
B. The function is not linear.
The given data points are:
\[
\begin{align*}
x: & \quad -2, \quad 0, \quad 2, \quad 4 \\
f(x): & \quad 11, \quad 6, \quad 11, \quad -4 \\
\end{align*}
\]
**Step 1: Calculate the differences in \( f(x) \)**
Let's find the values of \( f(x) \) for the successive pairs of \( x \):
- From \( x = -2 \) to \( x = 0 \):
\[
f(0) - f(-2) = 6 - 11 = -5
\]
- From \( x = 0 \) to \( x = 2 \):
\[
f(2) - f(0) = 11 - 6 = 5
\]
- From \( x = 2 \) to \( x = 4 \):
\[
f(4) - f(2) = -4 - 11 = -15
\]
**Step 2: Analyze the differences**
The differences in \( f(x) \) are not constant:
- The change from \( x = -2 \) to \( x = 0 \) is \( -5 \).
- The change from \( x = 0 \) to \( x = 2 \) is \( 5 \).
- The change from \( x = 2 \) to \( x = 4 \) is \( -15 \).
Since the differences are not consistent, \( f(x) \) does not represent a linear function.
**Conclusion:**
B. The function is not linear.
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