To find \( P(\text{blue or medium}) \), we can use the principle of inclusion-exclusion.
First, we need to find the probabilities of events \( A \) (being blue) and \( B \) (being medium).
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Find \( P(\text{blue}) \):
- Total blue items = 6
- Thus, \( P(\text{blue}) = \frac{6}{30} = \frac{1}{5} \).
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Find \( P(\text{medium}) \):
- Total medium items = 7
- Thus, \( P(\text{medium}) = \frac{7}{30} \).
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Find \( P(\text{blue and medium}) \):
- Blue and medium items = 1 (from the table).
- Thus, \( P(\text{blue and medium}) = \frac{1}{30} \).
Now we can apply the inclusion-exclusion principle:
\[ P(\text{blue or medium}) = P(\text{blue}) + P(\text{medium}) - P(\text{blue and medium}) \] \[ P(\text{blue or medium}) = \frac{6}{30} + \frac{7}{30} - \frac{1}{30} \] \[ P(\text{blue or medium}) = \frac{6 + 7 - 1}{30} = \frac{12}{30} \]
Now we simplify \( \frac{12}{30} \):
\[ \frac{12}{30} = \frac{2}{5} \]
Thus, the final result is
\[ \frac{12}{30} \text{ or } \frac{2}{5} \]
Based on the given options, the answer is:
\( \frac{12}{30} \).