x=x0+v0t+12at2

An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

60 m
60 m

32 m
32 m

30 m
30 m

17 m

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

Given the equation for the position of an object under constant acceleration:

\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]

where:

  • \( x_0 \) is the initial position,
  • \( v_0 \) is the initial velocity,
  • \( a \) is the acceleration,
  • \( t \) is the time.

In this case:

  • The initial position \( x_0 = 2 \) m,
  • The initial velocity \( v_0 = 15 \) m/s,
  • Since the object is moving at a constant speed, the acceleration \( a = 0 \) m/s².

Substituting the known values into the equation for time \( t = 1 \) s:

\[ x = 2 + 15(1) + \frac{1}{2} (0)(1^2) \]

Simplifying this:

\[ x = 2 + 15 + 0 \]

\[ x = 17 , \text{m} \]

Thus, the final position of the object after 1 second is 17 m.