To add the mixed numbers \(4 \frac{3}{5}\) and \(7 \frac{8}{15}\), we first convert them to improper fractions.
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Convert \(4 \frac{3}{5}\): \[ 4 \frac{3}{5} = \frac{4 \times 5 + 3}{5} = \frac{20 + 3}{5} = \frac{23}{5} \]
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Convert \(7 \frac{8}{15}\): \[ 7 \frac{8}{15} = \frac{7 \times 15 + 8}{15} = \frac{105 + 8}{15} = \frac{113}{15} \]
Now we add the two improper fractions \(\frac{23}{5}\) and \(\frac{113}{15}\). To do this, we need a common denominator. The least common multiple of 5 and 15 is 15.
- Convert \(\frac{23}{5}\) to have a denominator of 15: \[ \frac{23}{5} \times \frac{3}{3} = \frac{69}{15} \]
Now we can add the fractions: \[ \frac{69}{15} + \frac{113}{15} = \frac{69 + 113}{15} = \frac{182}{15} \]
Next, convert \(\frac{182}{15}\) back to a mixed number. Divide 182 by 15:
- \(182 \div 15 = 12\) remainder \(2\).
So we can write: \[ \frac{182}{15} = 12 \frac{2}{15} \]
Thus, the sum of \(4 \frac{3}{5} + 7 \frac{8}{15}\) is: \[ \boxed{12 \frac{2}{15}} \]