Use the data table to answer the question. It shows the acceleration of a body when a net force is applied to it.

Let's tackle each question one by one.

1. Net Force and Mass vs. Acceleration: The relationship between net force (F), mass (m), and acceleration (a) is given by Newton's second law, \( F = m \cdot a \). We can use this equation to find the missing acceleration when the net force is 20.0 N and mass is 5.0 kg.

   Using the equation: \[ a = \frac{F}{m} = \frac{20.0 , \text{N}}{5.0 , \text{kg}} = 4.0 , \text{m/s}^2 \]

   So, the value that would complete the last cell is 4.0.

2. Equation for Motion: We want to find the final position \( x \) after 1 second using the equation: \[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \] Given that the object is moving at a constant speed, the acceleration \( a \) is 0. Therefore, the equation simplifies to: \[ x = x_0 + v_0 t \] Plugging in the values:

   • \( x_0 = 2 , \text{m} \)
   • \( v_0 = 15 , \text{m/s} \)
   • \( t = 1 , \text{s} \)

   So: \[ x = 2 , \text{m} + 15 , \text{m/s} \cdot 1 , \text{s} = 2 , \text{m} + 15 , \text{m} = 17 , \text{m} \]

   The final position of the object after 1 second is 17 m.

3. Graph of an Object's Position Over Time: If the graph of an object's position over time is a horizontal line and \( y \) is not equal to 0, it indicates that the position is constant. This means that the object is not changing its position with respect to time.

   • A horizontal line indicates that the velocity is constant and non-zero (it is moving at a constant speed).
   • The acceleration would be 0 since the velocity is not changing.

   Therefore, the correct response is: The velocity is constant and non-zero.

In summary:

1. The missing acceleration is 4.0.
2. The final position after 1 second is 17 m.
3. The velocity is constant and non-zero.