Use the equation for motion to answer the question.

To find the final position of the object after 1 second, we will use the equation for motion:

\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]

Given the values:

• \( x_0 = 2 \) m (starting position)
• \( v_0 = 15 \) m/s (starting velocity)
• \( a = 0 \) m/s² (since the object is moving at a constant speed, the acceleration is zero)
• \( t = 1 \) s (time period)

Since the acceleration \( a = 0 \), the equation simplifies to:

\[ x = x_0 + v_0 t \] Substituting in the values:

\[ x = 2 , \text{m} + (15 , \text{m/s} \times 1 , \text{s}) \] \[ x = 2 , \text{m} + 15 , \text{m} \] \[ x = 17 , \text{m} \]

So the final position of the object after 1 second is 17 m.

The correct response is:

17 m