Use the equation for motion to answer the question.

Question

x=x0+v0t+1/2at^2

An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

60 m
60 m

30 m
30 m

17 m
17 m

32 m

Answer 1

To find the final position of the object after 1 second, we will use the equation for motion:

$$x=x_0+v_{0}t+\frac{1}{2}a{t}^2$$

Given the values:

• $x_0=2$ m (starting position)
• $v_0=15$ m/s (starting velocity)
• $a=0$ m/s² (since the object is moving at a constant speed, the acceleration is zero)
• $t=1$ s (time period)

Since the acceleration $a=0$, the equation simplifies to:

$$x=x_0+v_{0}t$$ Substituting in the values:

$$x=2,\text{m}+(15,\text{m/s}\times 1,\text{s})$$ $$x=2,\text{m}+15,\text{m}$$ $$x=17,\text{m}$$

So the final position of the object after 1 second is 17 m.

The correct response is:

17 m