Use the image to answer the question.

To determine which object would reach 100 feet in the least amount of time, we need to analyze the lines on the graph:

• Object A (solid line) has coordinates (0,0) to (3,6). This means that in 3 seconds, it travels 6 feet. The slope, which represents the rate of distance over time, is 2 feet per second (6 feet / 3 seconds). To find out how long it would take to reach 100 feet:

  \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{100 \text{ feet}}{2 \text{ feet/second}} = 50 \text{ seconds} \]

• Object B (dotted line) spans from (0,0) to (6,6), meaning it travels 6 feet in 6 seconds. The speed is 1 foot per second (6 feet / 6 seconds). The time to reach 100 feet would be:

  \[ \text{Time} = \frac{100 \text{ feet}}{1 \text{ foot/second}} = 100 \text{ seconds} \]

• Object C (dashed line) goes from (0,0) to (6,3), meaning it covers 3 feet in 6 seconds. The speed is 0.5 feet per second (3 feet / 6 seconds). Thus, the time to reach 100 feet is:

  \[ \text{Time} = \frac{100 \text{ feet}}{0.5 \text{ feet/second}} = 200 \text{ seconds} \]

Now we compare the times:

• Object A would take 50 seconds.
• Object B would take 100 seconds.
• Object C would take 200 seconds.

Conclusion: Object A reaches 100 feet in the least amount of time (50 seconds).

So, the correct answer is:

object A