The numbers are the sum of each row and column

To find the value of each symbol, we can set up a system of equations based on the information given.

Let's denote:

• Tulip as \( T \)
• Tree as \( R \)
• Sunflower as \( S \)
• Leaf as \( L \)

From the given information, we can write the following equations:

1. \( 2T + 2R = 28 \) (Equation 1)
2. \( 2S + 2R = 30 \) (Equation 2)
3. \( T + 3L = 18 \) (Equation 3)
4. \( 3L + R = 20 \) (Equation 4)

Now let’s simplify these equations:

From Equation 1: \[ T + R = 14 \quad (1) \]

From Equation 2: \[ S + R = 15 \quad (2) \]

Now we have:

1. \( T + R = 14 \)
2. \( S + R = 15 \)
3. \( T + 3L = 18 \)
4. \( 3L + R = 20 \)

From Equation (1), we can express \( R \) in terms of \( T \): \[ R = 14 - T \quad (3) \]

Substitute Equation (3) into Equation (2): \[ S + (14 - T) = 15 \] \[ S - T = 1 \quad (4) \] Thus, \( S = T + 1 \).

Now, let's substitute \( R \) from Equation (3) into Equation (4): \[ 3L + (14 - T) = 20 \] \[ 3L = 6 + T \] \[ L = 2 + \frac{T}{3} \quad (5) \]

Now, let’s substitute \( L \) back into Equation (3): \[ T + 3\left(2 + \frac{T}{3}\right) = 18 \] \[ T + 6 + T = 18 \] \[ 2T + 6 = 18 \] \[ 2T = 12 \] \[ T = 6 \]

Now, substitute \( T = 6 \) back into Equation (3): \[ R = 14 - T = 14 - 6 = 8 \]

Using Equation (4) to find \( S \): \[ S = T + 1 = 6 + 1 = 7 \]

Now substitute \( T = 6 \) into Equation (5) to find \( L \): \[ L = 2 + \frac{6}{3} = 2 + 2 = 4 \]

Thus, the values we found are:

• Tulip \( T = 6 \)
• Tree \( R = 8 \)
• Sunflower \( S = 7 \)
• Leaf \( L = 4 \)

Therefore, the value of the leaf \( L \) is \( \boxed{4} \).