The numbers are the sum of each row and column

Let's assign variables to each symbol:

• Tulip = \( T \)
• Tree = \( R \)
• Sunflower = \( S \)
• Leaf = \( L \)

Now we can write down the system of equations based on the provided statements:

1. \( 2T + 2R = 28 \)
2. \( 2S + 2R = 30 \)
3. \( T + 3L = 18 \)
4. \( 3L + R = 20 \)

Let's simplify each equation:

1. From \( 2T + 2R = 28 \), we can divide by 2: \[ T + R = 14 \quad \text{(Equation 1)} \]

2. From \( 2S + 2R = 30 \), we can divide by 2: \[ S + R = 15 \quad \text{(Equation 2)} \]

3. The third equation remains: \[ T + 3L = 18 \quad \text{(Equation 3)} \]

4. The fourth equation remains: \[ 3L + R = 20 \quad \text{(Equation 4)} \]

Next, we can manipulate these equations to find the variable values.

Step 1: Solve for \( R \)

From Equation 1: \[ R = 14 - T \quad \text{(Substituted into other equations)} \]

Step 2: Substitute \( R \) into Equation 2

Substituting \( R = 14 - T \) into Equation 2: \[ S + (14 - T) = 15 \ S - T = 1 \quad \text{(Equation 5)} \]

Step 3: Substitute \( R \) into Equation 4

Substituting \( R = 14 - T \) into Equation 4: \[ 3L + (14 - T) = 20 \ 3L - T = 6 \quad \text{(Equation 6)} \]

Step 4: Solve the system of Equations 3 and 6

Now we have:

• \( T + 3L = 18 \) (Equation 3)
• \( 3L - T = 6 \) (Equation 6)

We can add these two equations together to eliminate \( T \): \[ (T + 3L) + (3L - T) = 18 + 6 \ 6L = 24 \ L = 4 \]

Step 5: Substitute \( L \) back to find \( T \) and \( R \)

Substituting \( L = 4 \) into Equation 3: \[ T + 3(4) = 18 \ T + 12 = 18 \ T = 6 \]

Now substituting \( T = 6 \) into Equation 1 to find \( R \): \[ 6 + R = 14 \ R = 8 \]

Step 6: Substitute to find \( S \)

Now substituting \( T = 6 \) into Equation 5 to find \( S \): \[ S - 6 = 1 \ S = 7 \]

Summary of Values:

• Tulip \( T = 6 \)
• Tree \( R = 8 \)
• Sunflower \( S = 7 \)
• Leaf \( L = 4 \)

Thus, the value of the leaf \( L \) is \( \boxed{4} \).