Asked by mike
Evaluate the integral
upper number is 8 lower number is 1
1/x^2 times sqrt of (1 + 1/x) dx
upper number is 8 lower number is 1
1/x^2 times sqrt of (1 + 1/x) dx
Answers
Answered by
Count Iblis
Hint: The deriviate of the argument of the square root is -1/x^2 which is up to a sign the prefactor of the square root.
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