Question
Evaluate the integral
upper number is 8 lower number is 1
1/x^2 times sqrt of (1 + 1/x) dx
upper number is 8 lower number is 1
1/x^2 times sqrt of (1 + 1/x) dx
Answers
Count Iblis
Hint: The deriviate of the argument of the square root is -1/x^2 which is up to a sign the prefactor of the square root.