Bot GPT 4-o mini The magnitude of electrical charge on objects affects the electric force between them according to Coulomb's Law. According to this law, the electric force \( F \) between two point charges is directly proportional to the product of the magnitudes of their charges and inversely proportional to the square of the distance \( r \) between them. Mathematically, it is expressed as:
\[ F = k \frac{|q_1 \cdot q_2|}{r^2} \]
where:
- \( F \) is the magnitude of the electric force,
- \( k \) is Coulomb's constant,
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
- \( r \) is the distance between the centers of the two charges.
Based on this relationship:
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As the charge increases, the force increases in strength: This is correct. If either charge \( q_1 \) or \( q_2 \) increases, the product \( |q_1 \cdot q_2| \) increases, resulting in a stronger electric force.
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As the charge increases, the force decreases in strength: This is incorrect. An increase in charge leads to an increase in force.
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As the charge increases, the force becomes more negative: This statement is misleading. The force's direction (attractive or repulsive) depends on the signs of the charges, but the magnitude (which is treated as a positive value in the context of Coulomb's Law) will increase with increasing charge.
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As the charges increase, the forces become more attractive: This statement is not universally true. Whether the force is attractive or repulsive depends on the signs of the charges. Like charges repel each other, while opposite charges attract. An increase in the magnitude of either type of charge does amplify the force, but it does not change the nature of the force unless the sign of one or both charges is altered.
In summary, as the magnitude of electrical charge on objects increases, the electric force between them increases in strength (the first option).
1 answer