Asked by Susie
Under laboratory conditions of 25.0 degrees celcius and 99.5 kPa, what is the maximum number of cubic decimeters of ammonia that could be produced from 1.50 dm3 of nitrogen according to the following equation:
N2(g) + 3H2 (g) --> 2NH3(g)
I am not sure about this.
a) 3.22 dm3
b) 3.00 dm3
c) 2.70 dm3
d) 3.33 dm3
N2(g) + 3H2 (g) --> 2NH3(g)
I am not sure about this.
a) 3.22 dm3
b) 3.00 dm3
c) 2.70 dm3
d) 3.33 dm3
Answers
Answered by
DrBob222
When all of the materials are gases, you can use the coefficients to give the volume.
As follows:
1.5 dm^3 x (2 moles NH3/1 mole N2) = 1.5 dm^3 x (2/1) = ??
As follows:
1.5 dm^3 x (2 moles NH3/1 mole N2) = 1.5 dm^3 x (2/1) = ??
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