To find the slope and y-intercept of the equation \( 9 + 272x = -32y \), we first need to rewrite it in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
Starting with the given equation:
\[ 9 + 272x = -32y \]
First, we can isolate \( y \) by dividing the entire equation by -32 to solve for \( y \):
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Move \( 9 + 272x \) to the right side: \[ -32y = - (9 + 272x) \]
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This simplifies to: \[ -32y = -9 - 272x \]
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Now, divide every term by -32: \[ y = \frac{9}{32} + \frac{272}{32}x \] which simplifies to: \[ y = \frac{9}{32} - 8.5x \]
Now the equation is in the form \( y = mx + b \), where:
- The slope \( m = -8.5 \)
- The y-intercept \( b = \frac{9}{32} \)
The y-intercept as an ordered pair is \( (0, \frac{9}{32}) \).
Thus, the final answer is:
The slope is \(-8.5\). The y-intercept is \( (0, \frac{9}{32}) \).