Graph the linear equation

Question

Graph the linear equation

y=23x−1
.

(1 point)
Responses

An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis negative 2 comma negative 2 right parenthesis and left parenthesis 0 comma 1 right parenthesis.
Image with alt text: An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis negative 2 comma negative 2 right parenthesis and left parenthesis 0 comma 1 right parenthesis.

A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points.
The coordinates of the plotted points are as follows: left parenthesis 0 comma negative 2 right parenthesis, and left parenthesis 1 comma negative 9 right parenthesis.
Image with alt text: A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points. The coordinates of the plotted points are as follows: left parenthesis 0 comma negative 2 right parenthesis, and left parenthesis 1 comma negative 9 right parenthesis.

A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points.
The coordinates of the plotted points are as follows: left parenthesis 0 comma negative 1 right parenthesis, and left parenthesis 3 comma 1 right parenthesis.
Image with alt text: A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points. The coordinates of the plotted points are as follows: left parenthesis 0 comma negative 1 right parenthesis, and left parenthesis 3 comma 1 right parenthesis.

An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma negative 4 right parenthesis and left parenthesis 1 comma 2 right parenthesis.
Image with alt text: An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma negative 4 right parenthesis and left parenthesis 1 comma 2 right parenthesis.

Answer 1

Bot GPT 4-o mini answered
2 hours ago

To graph the linear equation \( y = 23x - 1 \), we can identify a couple of key points and the slope from the equation itself.

Y-Intercept: The y-intercept can be found by setting \( x = 0 \): \[ y = 23(0) - 1 = -1 \] So the point \( (0, -1) \) is on the graph.
Slope: The slope is \( 23 \). This means that for every unit increase in \( x \), \( y \) will increase by \( 23 \).
Finding Another Point: We can find another point by choosing a value for \( x \). Let's choose \( x = 1 \): \[ y = 23(1) - 1 = 22 \] Therefore, the point \( (1, 22) \) is also on the graph.

Now, plot the points \( (0, -1) \) and \( (1, 22) \) on the coordinate plane. Since the slope is steep, the line will rise quickly as \( x \) increases. Draw a straight line through these points and extend it with arrows in both directions.

Given the equation and the points calculated, the correct graph will have a line passing through \( (0, -1) \) and \( (1, 22) \).

Based on the options provided, it seems there isn't an exact match, but you should look for a graph with a steep upward slope, ideally passing through the y-intercept at \( (0, -1) \). If you see options with slopes matching the steep rise described, that would indicate the correct plot.