Question

What is 3/6 + 8/9 as a benchmark fraction

Answer 1

To add the fractions \( \frac{3}{6} \) and \( \frac{8}{9} \), we first simplify \( \frac{3}{6} = \frac{1}{2} \).

Next, we need a common denominator to add \( \frac{1}{2} \) and \( \frac{8}{9} \). The least common multiple (LCM) of 2 and 9 is 18.

Now, we convert both fractions to have a denominator of 18:

1. For \( \frac{1}{2} \):
\[
\frac{1}{2} = \frac{1 \times 9}{2 \times 9} = \frac{9}{18}
\]

2. For \( \frac{8}{9} \):
\[
\frac{8}{9} = \frac{8 \times 2}{9 \times 2} = \frac{16}{18}
\]

Now we can add the two fractions:
\[
\frac{9}{18} + \frac{16}{18} = \frac{25}{18}
\]

Thus, the sum \( \frac{3}{6} + \frac{8}{9} \) is \( \frac{25}{18} \).

As a mixed number, \( \frac{25}{18} \) can be expressed as:
\[
1 \frac{7}{18}
\]

So, the final answer is:
\[
\frac{25}{18} \text{ or } 1 \frac{7}{18}
\]