If you crossed a homozygous (BB) guinea pig for black fur color with a heterozygous (Bb) guinea pig for black fur color, what would be the predicted percentage of homozygous, black-furred guinea pigs?(1 point)

To determine the predicted percentage of homozygous black-furred guinea pigs from a cross between a homozygous (BB) guinea pig and a heterozygous (Bb) guinea pig, we can set up a simple Punnett square.

The genotypes of the parents are:

• Parent 1 (homozygous): BB
• Parent 2 (heterozygous): Bb

The possible gametes from each parent are:

• Parent 1 (BB) can only produce B gametes.
• Parent 2 (Bb) can produce B or b gametes.

Setting up the Punnett square:

| | B | B | |----|----|----| | B | BB | BB | | b | Bb | Bb |

From the Punnett square, we can see the following results:

• BB (homozygous black fur) = 2 out of 4
• Bb (heterozygous black fur) = 2 out of 4

Thus, the percentages are:

• Homozygous (BB): 2 out of 4 = 50%
• Heterozygous (Bb): 2 out of 4 = 50%

Therefore, the predicted percentage of homozygous black-furred guinea pigs is 50%.