To solve the inequality \(3x - 1 \le -10\), follow these steps:
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Add 1 to both sides to isolate the term with \(x\): \[ 3x - 1 + 1 \le -10 + 1 \] \[ 3x \le -9 \]
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Divide both sides by 3 to solve for \(x\): \[ x \le \frac{-9}{3} \] \[ x \le -3 \]
Therefore, the solution to the inequality is: \[ \boxed{x \le -3} \]