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Use the substitution method to solve the system 2x+3y=4 , −4x−6y=−8 .(1 point) Responses no solution no solution infinite solut...Question
Use the substitution method to solve the system 2x+3y=4 , −4x−6y=−8 .(1 point) Responses no solution no solution infinite solutions infinite solutions (2−1) left parenthesis 2 comma negative 1 right parenthesis (−1,2)
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Answered by
GPT-4o mini
To solve the system of equations using the substitution method, we will start with the two equations given:
1. \( 2x + 3y = 4 \)
2. \( -4x - 6y = -8 \)
Let's manipulate the first equation to express \( y \) in terms of \( x \):
1. From the first equation, we can isolate \( y \):
\[
3y = 4 - 2x
\]
\[
y = \frac{4 - 2x}{3}
\]
Now, let's substitute this expression for \( y \) back into the second equation.
2. Substitute \( y \) in the second equation:
\[
-4x - 6\left(\frac{4 - 2x}{3}\right) = -8
\]
To eliminate the fraction, multiply the entire equation by 3:
\[
-12x - 6(4 - 2x) = -24
\]
Now distribute \( -6 \):
\[
-12x - 24 + 12x = -24
\]
Now combine like terms:
\[
-24 = -24
\]
This is a true statement, which means the two equations represent the same line. Thus, there are infinitely many solutions to this system.
Therefore, the answer is:
**Infinite solutions.**
1. \( 2x + 3y = 4 \)
2. \( -4x - 6y = -8 \)
Let's manipulate the first equation to express \( y \) in terms of \( x \):
1. From the first equation, we can isolate \( y \):
\[
3y = 4 - 2x
\]
\[
y = \frac{4 - 2x}{3}
\]
Now, let's substitute this expression for \( y \) back into the second equation.
2. Substitute \( y \) in the second equation:
\[
-4x - 6\left(\frac{4 - 2x}{3}\right) = -8
\]
To eliminate the fraction, multiply the entire equation by 3:
\[
-12x - 6(4 - 2x) = -24
\]
Now distribute \( -6 \):
\[
-12x - 24 + 12x = -24
\]
Now combine like terms:
\[
-24 = -24
\]
This is a true statement, which means the two equations represent the same line. Thus, there are infinitely many solutions to this system.
Therefore, the answer is:
**Infinite solutions.**
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