Solve the following quadratic equation using the perfect square trinomial pattern: x^2−16x+64=0 .(1 point)

To solve the quadratic equation \( x^2 - 16x + 64 = 0 \) using the perfect square trinomial pattern, we first recognize that the left side can be factored.

The general form of a perfect square trinomial is \( (x - a)^2 = 0 \). In this case, we can see that:

\[ x^2 - 16x + 64 = (x - 8)^2 \]

So we rewrite the equation:

\[ (x - 8)^2 = 0 \]

Now, we can take the square root of both sides:

\[ x - 8 = 0 \]

Solving for \( x \):

\[ x = 8 \]

Thus, the solution to the equation \( x^2 - 16x + 64 = 0 \) is:

x = 8

So the correct response is:

x=8