The equation you provided seems to have a small mix-up, but we can work with it. I will interpret it as the linear equation:
\[ y = -\frac{2}{3}x + 4 \]
To graph this line, we can follow a series of steps:
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Identify the slope and the y-intercept:
- The slope (m) is \(-\frac{2}{3}\).
- The y-intercept (b) is \(4\), which means the line crosses the y-axis at the point \((0, 4)\).
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Plot the y-intercept:
- Start at the origin \((0, 0)\) on the Cartesian plane and move up to \(4\) on the y-axis. Place a point there: \((0, 4)\).
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Use the slope to find another point:
- From the y-intercept \((0, 4)\), use the slope \(-\frac{2}{3}\). This means that for every \(3\) units you move to the right (positive x-direction), you move \(2\) units down (negative y-direction).
- Starting from \((0, 4)\):
- Move \(3\) units to the right to get to \( (3, 4) \).
- Move down \(2\) units to arrive at the point \((3, 2)\).
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Plot the second point:
- Place a point at \((3, 2)\).
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Draw the line:
- Use a ruler to draw a straight line through the two points \((0, 4)\) and \((3, 2)\).
Additional Points:
To ensure accuracy, you can find more points using the equation:
- If \(x = 0\), then \(y = 4\) (already plotted)
- If \(x = 3\), then \(y = 2\) (already plotted)
- If \(x = -3\), then: \[ y = -\frac{2}{3}(-3) + 4 = 2 + 4 = 6 \] So the point \((-3, 6)\) can also be plotted.
You can plot this third point and ensure the line has the correct slope.
Final Graph:
Once you connect the points, you should have a graph of the line with \( y = -\frac{2}{3}x + 4 \) that accurately represents the relationship defined by the equation. The line will slope downwards from left to right, reflecting the negative slope of \(-\frac{2}{3}\).