Show which of the following points is part of the solution set for the inequality y≤25x+1 .(1 point) Responses (10,5.5) left parenthesis 10 comma 5.5 right parenthesis (−10,6) left parenthesis negative 10 comma 6 right parenthesis (10,4) left parenthesis 10 comma 4 right parenthesis (10,6)

To determine which of the given points is part of the solution set for the inequality \( y \leq 25x + 1 \), we can substitute each point into the inequality.

1. Point (10, 5.5):

   • Substitute \( x = 10 \) and \( y = 5.5 \): \[ 5.5 \leq 25(10) + 1 \ 5.5 \leq 250 + 1 \ 5.5 \leq 251 \quad \text{(True)} \]

2. Point (-10, 6):

   • Substitute \( x = -10 \) and \( y = 6 \): \[ 6 \leq 25(-10) + 1 \ 6 \leq -250 + 1 \ 6 \leq -249 \quad \text{(False)} \]

3. Point (10, 4):

   • Substitute \( x = 10 \) and \( y = 4 \): \[ 4 \leq 25(10) + 1 \ 4 \leq 250 + 1 \ 4 \leq 251 \quad \text{(True)} \]

4. Point (10, 6):

   • Substitute \( x = 10 \) and \( y = 6 \): \[ 6 \leq 25(10) + 1 \ 6 \leq 250 + 1 \ 6 \leq 251 \quad \text{(True)} \]

Now let's summarize the results:

• Point (10, 5.5) - True
• Point (-10, 6) - False
• Point (10, 4) - True
• Point (10, 6) - True

So, the points (10, 5.5), (10, 4), and (10, 6) are in the solution set for the inequality \( y \leq 25x + 1 \).